date_diff redshift. GETDATE ()関数 / CURRENT_DATE - 現在時刻 これは、現在の日時を取得するのに使います。. date_diff redshift

 
GETDATE ()関数 / CURRENT_DATE - 現在時刻 これは、現在の日時を取得するのに使います。date_diff redshift  0

This is the documentation for the Amazon Redshift Developer Guide - amazon-redshift-developer-guide/r_DATEDIFF_function. CREATE TABLE ORDERS ( ID INT , PRODUCT CHAR. You can create an Amazon Redshift table with a TEXT column, but it is converted to a VARCHAR (256) column that accepts variable-length values with a maximum of 256 characters. amazon-redshift; or ask your own question. What about bank holidays? The typical way this is handled is to create a Calendar table with one row per day for the next N years, with fields for year, month, week number, day etc and flags that determine whether it's a working day, holiday, weekend etc. amazon-redshift; Share. SQL Date Diff Business Days. In terms of performance, Amazon Redshift beats MySQL by a large margin with an impressive query time, especially when data is compressed. These strings can contain datetime separators (such as ' - ', ' / ', or ': ') and the following "dateparts" and. Compare this with RDS, which reaches 100 gibibytes to 64 TB for most database engines. The following code snippet provides an example of this behavior: SELECT datediff (DAYS, '2021-01-01'::DATE, '2021-02-01'::DATE) AS datediff_interval_output , datediff ('day', '2021-01-01. Currently I am only returning 1. To be clear, I need any year fraction as well (ie. SELECT t1. For example, month truncates to the first day of the month. I tested this query on Redshift with the help of Workbench J. The time between these two values is one second, but the result of applying the DATEDIFF function on these values is one year: DATEDIFF (YEAR , '2016-12-31 23:59:59' , '2017-01-01 00:00:00') = 11. date_to, DATEDIFF(DD, evnt. Short description. I know this question is a few years old- but I stumbled across it and. Date_trunc Function. If either argument is null, the result is NULL. Step 2: Add the Amazon Redshift cluster public key to the host's authorized keys file; Step 3: Configure the host to accept all of the Amazon Redshift cluster's IP addresses; Step 4: Get the public key for the host; Step 5: Create a manifest file; Step 6: Upload the manifest file to an Amazon S3 bucket; Step 7: Run the COPY command to load the data5. All in One Excel VBA Bundle. To use it use the following syntax: DATEDIFF (part, start, end) This is the documentation for the Amazon Redshift Developer Guide - amazon-redshift-developer-guide/r_DATEDIFF_function. Skipping non-business hours outside of 9-5. How to Take Datediff from 20200211000000 AND 20200211001820 in Amazon redshift as Looking the Data we can say there is difference of 3 Min How can this be Achieve Using Query. AUTO distribution. The following example finds the difference in number. Redshift is a little more complex and ties up more IT management on maintenance due to lack of. Value a is less than or equal to value b. select DATEDIFF(second, sysdate, sysdate + interval '30 seconds') select DATEDIFF(minute, sysdate, sysdate + interval '20 minutes')Redshift is designed for analytic workloads and delivers fast query and I/O performance for any dataset by using 2 key techniques ; columnar storage and massive parallel processing. Returns the difference between two dates or times for a given date. Expected Results: 12. Redshift クエリのパフォーマンス分析. Share. rahulbmv. 3x less expensive than Snowflake for on-demand pricing; Redshift is 1. Storage. select last_day (sysdate); last_day ------------ 2014-01-31. Datediff with join returning not expected result. Each value that Amazon Redshift stores or retrieves has a data type with a fixed set of associated properties. <code_block1> – The code block. date_trunc works only on the date type. HLLSKETCH type. Create 1 day ranges new_start and new_end. This will draw the distinct pairs of id's and dates out and rejoin them onto the dataset only where the joined dates are earlier than the row in question. c_timestamp) from table_1. Any help would be really. answered Mar 2, 2016 at 6:53. The function returns the result of subtracting the second argument from the third argument. This sql will give you the number of days between two dates as integer:. A string literal that defines the format of the timestamp value. However, if I use DATEDIFF(day,. The values in the SALETIME column are timestamps. For example, if date1 equals 2022-July-04 and date2 equals 2021-July-04, you would expect a difference of one year when you use the datediff function. Likewise is there any function in redshift that I could use to get the correct week number. However when i run the same logic on actual data. 0 / 60 / 24 as diff from mytable t. Consider SQL Server function to calculate the difference between 2 dates in weeks: SQL Server : -- Difference between Dec 22, 2011 and Dec 31, 2011 in weeks SELECT DATEDIFF ( week, '2011-12-22', '2011-12-31') ; -- Result: 1. This is the documentation for the Amazon Redshift Developer Guide - amazon-redshift-developer-guide/r_DATEDIFF_function. {date|timestamp} A date column, timestamp column, or an expression that implicitly converts to a date or timestamp. AWS Redshift clusters require some manual maintenance. CREATE FUNCTION public. createddate, table2. Specifically, DATEDIFF determines the number of datepart boundaries that are crossed between two expressions. I want to calculate the months_in_inventory by calculating the difference between a fixed_date and the inventory_date. select datediff (qtr, '1998-07-01', current_date); date_diff ----------- 40 (1 row) En este ejemplo, se unen las tablas SALES y LISTING para calcular cuántos días después de indicarse se vendieron los tickets de los listados 1000 a 1005. すでに実行されたSQLを分析したい場合は、そのSQLを実行した接続ユーザ(もしくはスーパーユーザ)でRedshiftに接続し、. The best way to approach this requirement would be to Create a Scalar Python UDF - Amazon Redshift that takes an input of two dates, then outputs the difference. g. I need to subtract 5 hours from sysdate in Redshift. Why is. Sorted by: 1. I want to calculate the months_in_inventory by calculating the difference between a fixed_date and the inventory_date. Redshift Create Table; Redshift DateDiff; ADVERTISEMENT. 0 Kudos. Snowflake: DATEDIFF('day', start, stop) AS days Talha September 20th, 2021 Redshift is a completely managed data warehouse service offered by Amazon Web Services. El nombre predeterminado de la columna para la función DATEDIFF es DATE_DIFF. This can be up to 128 TB per node, reaching potentially petabytes of data in a cluster. inventory_date::date))) * 12 + EXTRACT (month FROM age ('2020-12-20'::date. Specify an OLE DB server type other. Returns the difference between two dates or times for a given date part, such as a day. Securely store your files in an S3 bucket like unlimited storage, and you can connect it with Cloudfront to serve your content on a CDN network. 1 Answer. CASE is used to specify a result when there are multiple conditions. Feat (redshift,presto): transpile DATEADD, DATEDIFF to presto #1746. PROGRAMMING LANGUAGES Course Bundle - 54 Courses in 1 | 4 Mock Tests. 0. how to get exact time Difference between two column eg: col1 date is 2014-09-21 02:00:00 col2 date is 2014-09-22 01:00:00 output like result: 23:00:00 I am getting result like Hours M. Found the lock and removed the pending query. To manage disk space, the STL log views only retain approximately two to five days of log history, depending on log usage and available disk space. A date field or a call to. 该函数运行所依据的日期或时间值的特定部分(年、月或日、小时、分钟、秒、毫秒或微秒)。. Redshift Date Time Operations. Just to clarify SQL server seems to require DATEDIFF (datepart, recentDate, olderDate) as startdate and enddate are a bit nebulous. I am trying to calculate the number of days between two dates. I need to find the difference between start_date_time and end_date_time, such that, if difference is 1 day, then result should be 1. It would handle leap years. Automated snapshots retain all of the data required to restore a cluster from a snapshot. state and a. SELECT * FROM tickets t LEFT JOIN d_customer c ON c. date 2. purchase_date) between 0 and 2 ORDER BY. When you use the sysdate function with date_diff, be aware that the value the sysdate function returns is datetime. timeworkedfrom >= date_trunc ('month', current_date) - interval '6. You need to cast it to a timestamp instead, e. When an input value includes a time zone, Amazon Redshift uses the time zone to convert the value to UTC and stores the UTC value. 看起来Redshift支持两种可能的函数来计算两个DATE-like对象之间的时间间隔距离:DATEDIFF() &date_diff() 。下面的代码片断提供了这种行为的一个例子。 下面的代码片断提供了这种行为的一个例子。Amazon Redshift and PostgreSQL have a number of important differences that you must be aware of as you design and develop your data warehouse applications. NAME, table2. At the time of insertion date into the timestamp datatype column, the value of date will be implicitly converted into the fully timestamp value. Redshift will place the query in a paused state temporarily. Like most other SQL functions, you need to pass in arguments; for the DATE_PART function, you’ll pass in a date/timestamp/date field that you want to extract a date part from and specify the part you want removed. Saved searches Use saved searches to filter your results more quicklyStrange SQLite does not have a DATEDIFF function. Improve this answer. 0. BigQuery also supports a separate DATE_DIFF function that will return the difference between two date types, unlike the DATETIME_DIFF that only supports the datetime type. 1. 000') Then use. In this case, the function returns 1 year despite the fact that these dates are only one day apart. g. Snowflake vs Redshift - learn 10 differences between these DW. The formula assumes that Saturday and Sunday are not business days. The Redshift DATEDIFF function is used to calculate the difference between two date values based on the interval specified using. select. Redshift. Redshift querying data on dates. Redshift vs SQL Server: Pricing. Weekends. state = b. It would handle. If the first date is later than the second date, the result is positive; otherwise, the result is negative. In case this doesn’t work, reboot your cluster. For example, the following command doesn't return an error, even though it sets the time zone to an invalid value. Redshift's generate_series () function is a leader node only function and as such you cannot use it for downstream processing on the compute nodes. The operator XN PG Query Scan indicates that Amazon Redshift will run a query against the federated PostgreSQL database for this part of the query, we refer to this as the “federated subquery” in this post. In PostgreSQL, you can take the difference in years, multiply by 12 and add. date_from, evnt. how many days exist between date number one and date number two) you’d use something like DATE_DIFF(‘day’, ‘2019-01-01’, ‘2019-01-06’). VARBYTE type. The following table describes features and behavior in Amazon. 0. For example, adding three months or 12 days to a starting date. The first example in that case is not correct it should start with 6/1/2018 not 5/1/2018. An identifier literal or string of the specific part of the date value (for example, year, month, or day) that the function operates on. asked Oct 30, 2018 at 20:06. ex: date 1 1/27/2019 date 2 2/01/2019 output 1 in terms of days output 2 in terms of weeksDATEDIFF does not guarantee that the full number of the specified time units passed between 2 datetime values: -- Get difference in hours between 8:55 and 11:00 SELECT DATEDIFF (hh, '08:55', '11:00'); -- Returns 3 although only 2 hours and 5 minutes passed between times -- Get difference in months between Sep 30, 2011 and Nov 02, 2011. The terms derive from the colours red and. Then, the last_value function will take last value per row and the distinct removes all irrelevant rows from the output. But on the last day of the week (day Friday), the total number will reflect. I am able to convert above query in dynamic way which gives me the count for previous week which is 43 and it works fine. Each value that Amazon Redshift stores or retrieves has a data type with a fixed set of associated properties. These strings can contain datetime separators (such as ' - ', ' / ', or ': ') and the following "dateparts" and "timeparts". For example, because the common calendar starts from the year 1, the first decade (decade 1) is 0001-01-01 through 0009-12-31, and the second decade (decade 2) is 0010-01-01 through 0019-12-31. Snowflake is a complete SaaS offering that requires no maintenance. Collectives™ on Stack Overflow. Out of curiosity I executed: select datediff(day, getdate(), current_timestamp); and got the following error: function pg_catalog. Here is the code used in RS. The COPY command is able to read from multiple data files or multiple data streams simultaneously. – nrmad. In MySQL, we can use SEC_TO_TIME () to do this conversion easily. tobymao closed this as completed in #1746 3 weeks ago. Spark & PySpark SQL provides datediff() function to get the difference between two dates. Por exemplo, suponha que você esteja calculando a diferença em anos entre duas datas, 12-31-2008 e 01-01-2009. I am running on AWS Redshift tables and I get the following error: [Amazon] (500310) Invalid operation: COALESCE types character varying and integer cannot be matched; 1 statement failed. This function was run on 14 Jan which gives the result of 39. select * from tableA where to_char (date,"yyyyMMdd") = "20221220". El nombre predeterminado de la columna para la función DATEDIFF es DATE_DIFF. TIME: Only the time part. 7k 2 2 gold badges 53 53 silver badges 83 83 bronze badges. datediff (year, dob, current_date + interval '1 year' - interval '1 day') as age. The example above shows the result of DATE_DIFF for two days in succession. *, datediff (second, start_date, end_date) / 60. The following code makes use of concatenation and type casting to achieve the results we need! select (datediff ('sec', created_at, first_purchase_at)::varchar || ' second' )::interval from users. Following are rules for working with interval literals supported by Amazon Redshift. This can be replace by a recursive CTE (or keep a "dates" table on your database). 00. It appears that Redshift supports two possible functions for computing a time interval distance between two DATE -like objects: DATEDIFF () & date_diff (). TIME: Only the time part. This often happens only for a few minutes. Redshift is a little more complex and ties up more IT management on maintenance due to lack of. Currently I am only returning 1. Categories: Date/Time. Each cluster runs an Amazon Redshift engine and contains one or more databases. You can directly convert the format by specifying the cast operator ( ‘::’) such as ::date, ::time, ::timestamp after the date string literal. Select CASE WHEN eventdate IS NOT NULL then 1 ELSE 0 end as datestatus FROM table. row_number () over (partition by serialid, dateadd (dd,0, datediff (dd,0,dateadd (HH,8,createddatetime))) order by createddatetime desc) rnk. If you do not want to skip the rows, you will need to load the date into a VARCHAR field (which will not cause an error) and later you will need to convert the VARCHAR into a DATE. Each WEEK begins on Sunday, so there is one date part boundary between Saturday, 2017-10-14 and Sunday,. For example, because the common calendar starts from the year 1, the first decade (decade 1) is 0001-01-01 through 0009-12-31, and the second decade (decade 2) is 0010-01-01 through 0019-12-31. This question is in a. I would like to calculate number of days between two dates in redshift but the function should take into account the time that's mean day=0 if there is less than 24 hours between the dates like Timestampdiff function in MySQL. numbers WITH RECURSIVE number_series (number) AS ( SELECT 1 UNION ALL SELECT number + 1 FROM number_series. The DIFFERENCE function compares the American Soundex codes of two strings. Find out key distinctions in architecture, performance, scaling, pricing—and more!Amazon Redshift accepts different date formats, including ISO date time strings. How do I go about getting the first date of current year using Redshift? I am familiar with T-SQL/SQL in SSMS but I am not entirely sure how to do this in Redshift. An Editor area where you can enter and run your query. In SQL Server, there is a 3 argument verison of the DATEDIFF () function, where the result produces the number of date part periods between the two dates, with the dates being TRUNC-ed to the relevant date part. sql loop with id, date, and 1 additional field (in redshift) The scenario is: A patient is taking multiple medications (denoted by ndc) Each medication has a fill date with a corresponding fill_nbr. I think you need an alias for your subquery. The time zone for the return value. How to use Redshift DATEDIFF? 7. 00274 because of the leap year. eg: each ndc has fill_nbr = 1 as the initial fill. 90) within group (order by datediff(day, START_DATE, END_DATE) I am guessing that the problem is the date difference. to_char (current_date,'YYYYMMDD') =. LIMIT clauses, ORDER BY clauses, simple predicates, and complex expressions are pushed down to the connector to reduce the amount of data scanned and decrease query execution run time. Redshift provides the different types of built-in functions to perform the different operations on the data as per user requirements. Redshift DATEDIFF Function. So, you cannot do what you want that simply. Share. Snowflake is a complete SaaS offering that requires no maintenance. The DateDiff function used in redshift has three arguments in it, we specify the dates for which we want to find the difference. With a simple where clause, we tried to filter out rows from the data set. In Google BigQuery and Amazon Redshift, the <date_part> is passed in as the first argument and the <date/time field> is the second argument. 3333 etc. SELECT DATEDIFF (day, '2019-12-05 08:09:55', GETDATE ()); Result: 39. A data type constrains the set of values that a column or argument can contain. Skipping weekends. The spectrum allows for a seamless analysis since it is directly embedded into the Amazons framework. Returns the <date> with the specified number <interval> added to the specified <date_part> of that date. WITH DateCte AS ( SELECT idcode, mydatetime, RANK () OVER ( ORDER BY idcode) AS CurrentRank, (RANK () OVER ( ORDER BY idcode) + 1 )AS NextRank FROM Table1 ) SELECT ce. Redshift Create Table; Redshift DateDiff; ADVERTISEMENT. Define a DECIMAL column in a table by specifying a precision and scale:Redshift is also a traditional data warehouse designed to tackle Business Intelligence use cases, among other things. usa_start_datetime::timestamp,u1. Example. Anybody help what is the equivalent of Dateadd and Datediff in DBeaver or anybody can convert this code in DBeaver. PDF RSS. Mysql has a function called Week() where we can use the mode to get the desired result. When an input value includes a time zone, Amazon Redshift uses the time zone to convert the value to UTC and stores the UTC value. 000','2014-09-23 01:23:45. 例如,假设您计算. Datetime types. Coalesce function is also known as NVL function in redshift. The following example table TIME_TEST has a column TIME_VAL (type TIME) with three values inserted. These dates both have the same year, and as such, the DATEDIFF function returns 0. replace (tzinfo=None), cast (MyTable. At this time, Amazon Redshift version 1. The default timestamp for a date value is 00:00:00. date1)) AS difference FROM t t1 INNER JOIN t t2 ON t1. Before we get started, a few basics. When the table grows larger, Amazon Redshift might change the distribution. AWS Collective See more. You shouldn't be converting to time - it is meant to store a point in time on a single 24h clock, not a duration or interval (even one that is constrained on its own to < 24 hours, which clearly your data is not). If you want to retain the log data, you will need to periodically copy it to other. DateDiff Bigint Datetime in Redshift for Min Difference. The default column name for a DATEADD function is DATE_ADD. dd/mm/yyyy), which makes me suspect that your SQL implementation is set up to parse them as some other format (e. 0. DATEADD ('week', 1, [due date]) Add 280 days to the date February 20, 2021. Answer to How do I calculate age as YY from date of birth asStep 2: Add the Amazon Redshift cluster public key to the host's authorized keys file; Step 3: Configure the host to accept all of the Amazon Redshift cluster's IP addresses; Step 4: Get the public key for the host; Step 5: Create a manifest file; Step 6: Upload the manifest file to an Amazon S3 bucket; Step 7: Run the COPY command to load the dataHow to create a SQL Server Linked Server to Amazon Redshift. 2. You can use window functions: select wa. Instead you can take the datediff in the smallest interval required (in your case, seconds), and then perform some math and string manipulation to present. ai; Redshift Date functions: Current date functions. most_recent) However, I am running into issues where the timestamp is the same. Add a comment. Amazon Redshift allocates the workload to the cluster nodes and. 128-bit signed integers with up to 38 digits of precision. fromtimestamp (epoch) ' LANGUAGE plpythonu IMMUTABLE; See Redshift documentation on UDF for details. Summary: in this tutorial, you will learn how to use the SQL Server DATEPART() function to extract a part of a date. Unfortunately this. Use an interval literal to identify specific periods of time, such as 12 hours or 6 weeks. DECLARE @Date0 date = '2016-04-07'; -- Thursday. See Presto documentation for date_diff()-- the unit is regular varchar, so it needs to go in single quotes: date_diff('day', ts_from, ts_to) Share. If the result is positive, the Secure Agent returns negative values and if the result is negative, the positive value is returned. agency. When an input value includes a time zone, Amazon. For possible values, see Date parts for date or timestamp functions. It has the ability to maintain consistent SLAs and improve the throughput by over 35 times simultaneously. The following queries show an example of how to calculate the completion_days as the difference between eco_date and orginated_date. 3. You can create an Amazon Redshift column with a BPCHAR (blank-padded character) type, which Amazon Redshift converts to a fixed-length CHAR (256) column. The date function used to returns the difference between two date or datetime values as a given unit of duration. The DATEPART() function returns an integer which is a part of a date such as a day, month, and year. For example, DATEDIFF('week', '06-01-2021', '06-28-2021') returns 4 This function can be used to. There are two types of CASE expressions: simple and searched. Public Holiday. 8XL clusters with equivalently sized Medium, Large and X-Large Snowflake configurations: Redshift is 1. Some immediate benefits this will give us: Easier to. Share. g. how to get date difference between two dates using DateDiff Excluding the weekends. Arguments. DATEDIFF(DAY, '8/4/2014', '8/5/2014') +1 You need to add 1 to the DATEDIFF function and it will work as you want. The examples for aggregation extensions use the orders table, which holds sales data for an electronics company. Amazon Redshift Advisor offers recommendations about how to optimize your Amazon Redshift cluster to increase performance and save on operating costs. In PostgreSQL, you can take the difference in years, multiply by 12 and add. AWS Redshift vs Snowflake: A quick comparison. You were missing a closing semicolon inside the UPDATE statement. CDT. 6) but when I execute it in Redshift as UDF, it gives me incorrect output. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. amazon-redshift; or ask your own question. 例えば、 12-31-2008 と 01-01-2009 の 2 つの日付間で年の差を計算しているとします。. For example, the dateadd() is one of the functions provided by Redshift. You can use the OID columns in the Postgres catalog tables as joining columns. Amazon Redshift data type RDS MySQL or Aurora MySQL data type Description ; BOOLEAN : TINYINT(1) Logical Boolean (true or false) SMALLINT : TINYINT(UNSIGNED) Signed two-byte integer : SMALLINT : SMALLINT : Signed two-byte integer : INTEGER : SMALLINT UNSIGNED: Signed four-byte integer : INTEGER : MEDIUMINT (UNSIGNED)This example enumerates all dates between 2013-12-15 and 2014-01-02 (inclusively). An Amazon Redshift data warehouse is a collection of computing resources called nodes, which are organized into a group called a cluster. user where createddate >= '2019-09-01' and createddate <= '2019-09-30'. In this article, Let us see a Spark SQL Dataframe example of how to calculate a Datediff between two dates in seconds, minutes, hours, days, and months using Scala language and functions like datediff(), unix_timestamp(), to_timestamp(),. Create timestampdiif function in Redshift. Redshift starts at as low as $0. I spent some time looking for the best answer, and I think I have it. 53 sec compared to 41. Amazon Redshift interprets the DECADE or DECADES DATEPART based on the common calendar. DATEADD ('week', 1, [due date]) Add 280 days to the date February 20, 2021. After the opening of the console and query editor tool select schedule with different information such as authentication, Name of schedule query. Question: How can I take a start timestamp (created_at) and end timestamp (ended_at) and add a column that adds 1 month to the start timestamp until the end timestamp. DATEDIFF (date1, date2) You have three parameters in your DATEDIFF call. Need to set max_recursion_rows else redshift will stop you from doing too deep of a recursion. The best solution is to combineto use Redshift function DATEDIFF. The second date in the comparison. Now I am trying to make this query dynamic such that it can give me count for past 6 weeks starting from 44 to 39 not including current week something like below as an output: Count Week ------------ 124 W44 125 W43 126 W42 127 W41 128 W40 129 W39. If you want to get 1. 0 / 60 / 24 as diff from mytable t. Count ----- 124. sql. For example, if you are calculating the difference in years between two dates, 12-31-2008 and 01-01-2009, the function returns 1 year despite the fact that these dates are only one day apart. MONTHS_BETWEEN function. The Amazon Redshift version when the query ran. Merging files by client id and id. Date and Min Item number RELATED that that date. Redshift has a strict mode that is turned off by default - TO_DATE(string, format, is_strict=false). Follow. In the elastic resize, the cluster will be unavailable briefly. Neste caso, a função retorna 1 ano, apesar do fato de que essas datas são apenas um dia de diferença. Performance. Redshift Date Time Operations. And only do that for one day ranges. The default timestamp without time zone (TIMESTAMP) format is YYYY-MM-DD HH:MI:SS. In most use cases, Snowflake correctly handles date and timestamp values formatted as strings. However, since the requirement is to generate monthly reports which I would assume to be a. How to use Redshift DATEDIFF? 0. In this example, PID 19813 is holding the lock. the data type for the date colunm is timestamp without time zone in redshift. Note. For example, SELECT DATEDIFF (day, '2036-03-01', '2036-02-28'); returns -2, hinting that 2036 must be a leap year. DATE_DIFF function Examples. – Spark & PySpark SQL provides datediff() function to get the difference between two dates. What is the use of DATEDIFF in redshift? Redshift date_trunc. Getting the differences between two specified time values where the time is specified in the format of YYYY-MM-DD HH-MM-SS. Write resolution instructions: Use bullets, numbers and additional headings Add Screenshots to explain the resolution Add diagrams to explain complicated technical details, keep the diagrams in lucidchart or in google slide (keep it shared with entire Snowflake), and add the link of the source material in the Internal comment section Go in. Already have an account?I have a datediff() function that throws an exception. The DATE_PART function allows you to extract a specified date part from a date/time. However, we will have to exclude. DATEDIFF. Redshift offers two main types of nodes, DC2 and RA3. These strings can contain datetime separators (such as ' - ', ' / ', or ': ') and the following "dateparts" and "timeparts". Formats that include a time zone ( TZ, tz, or OF) are not supported as input. NOTE: The table I applied the query on had column/field 'datetime' of type 'timestamp'. MONTHS_BETWEEN is a good solution to this problem. Datetime types. The problem is not clear but assuming the requirement is to create month end dates between start and end dates with the given interval as months. select to_date ( '20010631', 'YYYYMMDD', FALSE ); The result is July 1, 2001, because there are only 30 days. A fully managed No-code Data Pipeline platform like Hevo Data helps you integrate and load data from 100+ different sources (including 40+ free sources) to a Data Warehouse such as Amazon Redshift or Destination of your choice in real-time in an effortless manner.